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Diameter squared X .785 X Height x 7.49 = cubic feet of water.
Mark
Maybe I'm not thinking through it right. But as it is in my mind, there is no circle anymore. So there is no diameter, circumference, or radius. Unless there is a divisible somewhere in there.
Maybe I'm not thinking through it right. But as it is in my mind, there is no circle anymore. So there is no diameter, circumference, or radius. Unless there is a divisible somewhere in there.
No?
J.C.
To solve the problem you have to define the whole space (volume of the cylinder then work backwards from that as the equation does)... So yes you still need Radius ect...
Maybe I'm not thinking through it right. But as it is in my mind, there is no circle anymore. So there is no diameter, circumference, or radius. Unless there is a divisible somewhere in there.
No?
J.C.
I missed that it was on it's side.
Mark
"Somewhere a Village is Missing Twelve Idiots!" - Casey Anthony
Push sticks/blocks Save Fingers
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"The true measure of a man is how he treats someone who can do him absolutely no good."
attributed to Samuel Johnson
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PUBLIC NOTICE: Due to recent budget cuts, the rising cost of electricity, gas, and oil...plus the current state of the economy............the light at the end of the tunnel, has been turned off.
Imagine a 50 gallon round tank on it's side. You have access at the top to measure the amount of liquid inside with a stick. You can obviously measure the depth and calculate when you have 25 gallons i.e. half full.
But how much is left in the tank if it's below the halfway point say...half of that?
Not sure of dimensions. How 'bout 32"x22".
Thanks.
(Heard this on the radio. Can't remember how to get to the answer. )
J.C.
Why not dump the water out into 5 gallon buckets and get a direct measurement?
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