Mike

It boils down to simple Ohms Law, E = I * R (Voltage = Current * Resistance). When wired for 120V the motor has an internal resistance of approximately 9 ohms and draws 13 amps. When wired for 240V it has an internal resistance of approximately 37 ohms and draws 6.5 amps. It is a single-phase motor; hence there are not multiple legs and it draws a total of 6.5 amps when wired in this configuration as stated on the manufactures plate affixed to the motor. You are correct, the higher the current draw the lower the gage of wire (larger diameter) is needed.

Hope this helps clarify it.

Woodslayer

It boils down to simple Ohms Law, E = I * R (Voltage = Current * Resistance). When wired for 120V the motor has an internal resistance of approximately 9 ohms and draws 13 amps. When wired for 240V it has an internal resistance of approximately 37 ohms and draws 6.5 amps. It is a single-phase motor; hence there are not multiple legs and it draws a total of 6.5 amps when wired in this configuration as stated on the manufactures plate affixed to the motor. You are correct, the higher the current draw the lower the gage of wire (larger diameter) is needed.

Hope this helps clarify it.

Woodslayer

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