So General 3080 has a 20 HP Honda. They say 8gpm @3000, is this not acurate either? Seems like 5 extra HP has to count for something?
I better get this hammered out asap!!! I'm not gonna pay for something that isnt gonna perform as needed!
Here are some more specs on it. It also has a reduced gearbox. It uses a 25 HP Subaru vs. the Honda that comes on the Gas version. I'm going to call them tomorrow and ask for some video showing the thing in action if they have any. They said they have a whole gauge set up to test flows and pressures.
Let me know what questions I should ask and I will report back so you all can help mr make the right decision.
Well converting a gas engine to run propane is not all that hard. Like I said I plan on doing my Spartan Trailer jet. Now that I been reading some of the conversion kit sites, I might even do my cart jetter as well. They say you will get the same HP out of the motor using propane.
But remember propane is not as explosive as gas and doesn't make the same HP. So I don't think you will get 25 hp out of a converted gasoline motor. If the 25hp motor is designed as a 25hp propane motor not a conversion then the 25hp rating may be accurate. Edit I should not have used the word explosive it is BTU's . Propane has a higher octane rating but doesn't make the same amount of heat as gas. And you need to alter the compression ratio to get the benifts of the higher octane rating to make the same HP. Thats why I said a converted gas engine vs. one made to be a propane engine.
Last edited by Cuda; 01-02-2011 at 05:48 PM. Reason: wrong wording
power = pressure x volumetric flow rate
in the units we are used to seeing, hp=(psi*gpm)/1714
so 8.5*3500/1714= 17 hp
some is lost to pump efficiency, so you need more than the formula says, some also to driving the gearbox, etc. find it hard to believe 25 would not do it though.
I thought / 1750 was for hydraulic, and for an industrial gas engine the number was 1250?
it has nothing to do with any engine or hydraulic or anything; it's just physics; power= flow x pressure. the 1714 is just a consequense of using psi and gpm and horsepower for the units in which you express power, flow, and pressure.
This is off the General Pump web site faq
Q. How do I calculate the horsepower required for my system?
A. The horsepower required for operation is based on three variables: discharge volume, pressure and drive type. The formula for the calculation is H=(P*G)/C.
Where: H = Horsepower
P = Pressure in PSI
G = Flow in GPM
C = Drive constant:
Hydraulic C = 1714
Electric C = 1460
Gasoline C = 1250 (Industrial grade)
Gasoline C = 1100 (Standard grade)
Diesel C = Supplied by Engine Mfr.